2011造价工程师《案例分析》真题答案
来源 :中华考试网 2016-08-22
中二【答案】
1.计算如下:
(1)260×[1+(P/F,8%,30)]+260×10%×(P/F,8%,30)=288.42元/m2
(2)90×[1+(P/F,8%,15)+(P/F,8%,30)+(P/F,8%,45)]+90×20%×[(P/F,8%,15)+(P/F,8%,30)+(P/F,8%,45)]+35=173.16元/m2
(3)80×[1+(P/F,8%,10)+(P/F,8%,20)+(P/F,8%,30)+(P/F,8%,40)]+80×20%×[(P/F,8%,10)+(P/F,8%,20)+P/F,8%,30)+(P/F,8%,40)]+35=194.02元/m2
方案二为最优方案,因其综合单价现值最低。
2.计算如下:
(1)14+20+40=74
14/74=0.18920/74=0.27040/74=0.541
(2)16.8+14.5+37.4=68.7
16.8/68.7=0.24514.5/68.7=0.21137.4/68.7=0.544
(3)1)0.189/0.245=0.771
2)0.27/0.211=1.280
3)0.541/0.544=0.994
改进顺序:找平层――防水层――保温层