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计算机软考程序员常考基础必知必会(36)

2016-4-18编辑:ljnbset

C++操作符优先级:

  记忆方法:

  去掉一个最高的,去掉一个最低的,剩下的是一、二、三、赋值;双目运算符中,顺序为算术、关系和逻辑,移位和逻辑位插入其中。

--摘自《C语言程序设计实用问答》

  问题:如何记住运算符的15种优先级和结合性?

  解答:C语言中运算符种类比较繁多,优先级有15种,结合性有两种。

  如何记忆两种结合性和15种优先级?下面讲述一种记忆方法。

  结合性有两种,一种是自左至右,另一种是自右至左,大部分运算符的结合性是自左至右,只有单目运算符、三目运算符的赋值运算符的结合性自右至左。

  优先级有15种,记忆方法如下:

  记住一个最高的:构造类型的元素或成员以及小括号。

  记住一个最低的:逗号运算符。

  剩余的是一、二、三、赋值——意思是单目、双目、三目和赋值运算符。

  在诸多运算符中,又分为:算术、关系、逻辑。

  两种位操作运算符中,移位运算符在算术运算符后边,逻辑位运算符在逻辑运算符的前面。

  再细分如下:

  算术运算符*,/,%高于+,-。

  关系运算符中:>,>=,<和<=高于==,!=。

  逻辑运算符中,除了逻辑求反(!)是单目外,逻辑与(&&)高于逻辑或(||)。

  逻辑位运算符中,除了逻辑按位求反(~)外,按位与(&)高于按位半加(^),高于按位或(|)。

Prece dence

Operator

Description

Example

Over loadable

Associativity

1

::

Scope resolution operator

Class::age = 2;

no

left to right

2

()

Function call

printf(“Hello world\n”);

yes

left to right

()

Member initalization

c_tor(int x, int y) : _x(x), _y(y * 10) {}

yes

[]

Array access

array[4] = 2;

yes

->

Member access from a pointer

ptr->age = 34;

yes

.

Member access from an object

obj.age = 34;

no

++

Post-increment

for (int i = 0; i < 10; i++) cout << i;

yes

--

Post-decrement

for (int i = 10; i > 0; i--) cout << i;

yes

dynamic_cast

Runtime-checked type conversion

Y& y = dynamic_cast(x);

no

static_cast

Unchecked type conversion

Y& y = static_cast(x);

no

reinterpret_cast

Reinterpreting type conversion

int const* p = reinterpret_cast(0x1234);

no

const_cast

Cast away/Add constness

int* q = const_cast(p);

no

typeid

Get type information

std::type_info const& t = typeid(x);

no

3

!

Logical negation

if (!done) ...

yes

right to left

not

Alternate spelling for !

~

Bitwise complement

flags = ~flags;

yes

compl

Alternate spelling for ~

++

Pre-increment

for (i = 0; i < 10; ++i) cout << i;

yes

--

Pre-decrement

for (i = 10; i > 0; --i) cout << i;

yes

-

Unary minus

int i = -1;

yes

+

Unary plus

int i = +1;

yes

*

Dereference

int data = *intPtr;

yes

&

Address of

int *intPtr = &data;

yes

sizeof

Size (of the type) of the operand in bytes

size_t s = sizeof(int);

no

new

Dynamic memory allocation

long* pVar = new long;

yes

new []

Dynamic memory allocation of array

long* array = new long[20];

yes

delete

Deallocating the memory

delete pVar;

yes

delete []

Deallocating the memory of array

delete [] array;

yes

(type)

Cast to a given type

int i = (int)floatNum;

yes

4

->*

Member pointer selector

ptr->*var = 24;

yes

left to right

.*

Member object selector

obj.*var = 24;

no

5

*

Multiplication

int i = 2 * 4;

yes

left to right

/

Division

float f = 10.0 / 3.0;

yes

%

Modulus

int rem = 4 % 3;

yes

6

+

Addition

int i = 2 + 3;

yes

left to right

-

Subtraction

int i = 5 - 1;

yes

7

<<

Bitwise shift left

int flags = 33 << 1;

yes

left to right

>>

Bitwise shift right

int flags = 33 >> 1;

yes

8

<

Comparison less-than

if (i < 42) ...

yes

left to right

<=

Comparison less-than-or-equal-to

if (i <= 42) ...

yes

>

Comparison greater-than

if (i > 42) ...

yes

>=

Comparison greater-than-or-equal-to

if (i >= 42) ...

yes

9

==

Comparison equal-to

if (i == 42) ...

yes

left to right

eq

Alternate spelling for ==

!=

Comparison not-equal-to

if (i != 42) ...

yes

not_eq

Alternate spelling for !=

10

&

Bitwise AND

flags = flags & 42;

yes

left to right

bitand

Alternate spelling for &

11

^

Bitwise exclusive OR (XOR)

flags = flags ^ 42;

yes

left to right

xor

Alternate spelling for ^

12

|

Bitwise inclusive (normal) OR

flags = flags | 42;

yes

left to right

bitor

Alternate spelling for |

13

&&

Logical AND

if (conditionA && conditionB) ...

yes

left to right

and

Alternate spelling for &&

14

||

Logical OR

if (conditionA || conditionB) ...

yes

left to right

or

Alternate spelling for ||

15

? :

Ternary conditional (if-then-else)

int i = a > b ? a : b;

no

right to left

16

=

Assignment operator

int a = b;

yes

right to left

+=

Increment and assign

a += 3;

yes

-=

Decrement and assign

b -= 4;

yes

*=

Multiply and assign

a *= 5;

yes

/=

Divide and assign

a /= 2;

yes

%=

Modulo and assign

a %= 3;

yes

&=

Bitwise AND and assign

flags &= new_flags;

yes

and_eq

Alternate spelling for &=

^=

Bitwise exclusive or (XOR) and assign

flags ^= new_flags;

yes

xor_eq

Alternate spelling for ^=

|=

Bitwise normal OR and assign

flags |= new_flags;

yes

or_eq

Alternate spelling for |=

<<=

Bitwise shift left and assign

flags <<= 2;

yes

>>=

Bitwise shift right and assign

flags >>= 2;

yes

17

throw

throw exception

throw EClass(“Message”);

no

 

18

,

Sequential evaluation operator

for (i = 0, j = 0; i < 10; i++, j++) ...

yes

left to right

计算机软考程序员常考基础必知必会(35)

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