python时间处理
来源 :中华考试网 2020-10-27
中在实际中遇到一个时间处理问题，需要将 Sep 06, 2014 19:30 (UTC 时间) 和 当前时间比较早晚，知道 此 2014-09-06 19:30 格式时间的运算。因此，在处理时，就想
先将sep 格式时间转化成 后面一个格式的时间样子，没有找到相关函数，于是自己简单的写了个程序，仅记于此，以备查询
代码如下：
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# -*- coding: utf-8 -*- from datetime import datefrom datetime import datetimefrom datetime import timedelta # # #如果是返回当前时间，可以简单的写成# # time.localtime()# # #这个返回UTC时间# # time.gmtime()# lt = time.localtime()# tm = time.gmtime()# ft = time.strftime('%Y-%m-%d %H-%M',lt)# ft2 = time.strftime('%Y-%m-%d %H:%M',tm)# print ft, ft2# print '--------------------------------------------------------'# now = datetime.datetime.now()# now = now.replace(day = 1)# print now# print now.time()## mytime = ['2014-09-06 20:19']# #mytime2 = '2014-10-09 14:32'# str = "".join(mytime)# print str# retime = datetime.strptime(str,'%Y-%m-%d %H:%M')# print retime# retime = retime +timedelta(hours = 8)# print retime## tdtime = datetime.now()# print tdtime# if retime <= tdtime - timedelta(days = 7):# print "too early"## #Sep 06, 2014 19:30 monthdic = {'Jan':'01', 'Feb':'02', 'Mar':'03', 'Apr':'04', 'May':'05', 'Jun':'06', 'Jul':'07', 'Aug':'08', 'Sep':'09', 'Oct':'10', 'Nov':'11', 'Dec':'12'}def time_format(timestr): timestr = timestr.replace(',','') #print timestr timelist = timestr.split() #print timelist mon = "".join(timelist[0]) #print mon timelist[0] = monthdic[mon] #print timelist mytime = "".join(timelist[2])+'-'+"".join(timelist[0])+'-'+"".join(timelist[1])+' '+ "".join(timelist[3]) return mytimeif __name__ == '__main__': timestr = 'Sep 06, 2014 19:30' str = time_format(timestr) print str mytime = datetime.strptime(str,'%Y-%m-%d %H:%M') print mytime mytime = mytime +timedelta(hours = 8) print mytime tdtime = datetime.now() print tdtime if mytime <= tdtime - timedelta(days = 7): print "too early" |